Другие языки программирования и технологии

*Кто поможет мне создать "сложный запрос" в БД?) )

BL
Bruce Lee
33
> *Кто поможет мне создать "сложный запрос" в БД? ) )

SELECT SUBSTR(exp, 1, 20) "expression", (CASE WHEN SUBSTR(exp, 6, 1) = '+' THEN (CASE WHEN SUBSTR(exp, 3, 1) = '+' THEN TO_NUMBER(SUBSTR(exp, 1, 2))
+ TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE WHEN SUBSTR(exp, 3, 1) = '-' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) - TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE
WHEN SUBSTR(exp, 3, 1) = '*' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) * TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE WHEN SUBSTR(exp, 3, 1) = '/' THEN
TO_NUMBER(SUBSTR(exp, 1, 2)) / TO_NUMBER(SUBSTR(exp, 4, 2)) END END END END) + TO_NUMBER(SUBSTR(exp, 7, 2)) ELSE CASE WHEN SUBSTR(exp, 6, 1) = '-'
THEN (CASE WHEN SUBSTR(exp, 3, 1) = '+' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) + TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE WHEN SUBSTR(exp, 3, 1) = '-' THEN
TO_NUMBER(SUBSTR(exp, 1, 2)) - TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE WHEN SUBSTR(exp, 3, 1) = '*' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) *
TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE WHEN SUBSTR(exp, 3, 1) = '/' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) / TO_NUMBER(SUBSTR(exp, 4, 2)) END END END END)
- TO_NUMBER(SUBSTR(exp, 7, 2)) ELSE CASE WHEN SUBSTR(exp, 6, 1) = '*' THEN (CASE WHEN SUBSTR(exp, 3, 1) = '+' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) +
TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE WHEN SUBSTR(exp, 3, 1) = '-' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) - TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE WHEN
SUBSTR(exp, 3, 1) = '*' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) * TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE WHEN SUBSTR(exp, 3, 1) = '/' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) /
TO_NUMBER(SUBSTR(exp, 4, 2)) END END END END) * TO_NUMBER(SUBSTR(exp, 7, 2)) ELSE CASE WHEN SUBSTR(exp, 6, 1) = '/' THEN (CASE WHEN SUBSTR(exp, 3, 1) = '+' THEN
TO_NUMBER(SUBSTR(exp, 1, 2)) + TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE WHEN SUBSTR(exp, 3, 1) = '-' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) - TO_NUMBER(SUBSTR(exp, 4, 2))
ELSE CASE WHEN SUBSTR(exp, 3, 1) = '*' THEN TO_NUMBER(SUBSTR(exp, 1, 2)) * TO_NUMBER(SUBSTR(exp, 4, 2)) ELSE CASE WHEN SUBSTR(exp, 3, 1) = '/' THEN
TO_NUMBER(SUBSTR(exp, 1, 2)) / TO_NUMBER(SUBSTR(exp, 4, 2)) END END END END) / TO_NUMBER(SUBSTR(exp, 7, 2)) END END END END) "result" FROM lab3_2;
Андрей Ким
Андрей Ким
1 769
Лучший ответ
А вот такой запрос - простой или сложный? :

SELECT *
FROM MYTABLE
STARTING WITH FIELD1=8
FOLLOWED BY NEXT FIELD2=FIELD1
S0
Sasha 007
63 137
Ну даже не знаю... =)Смотря по какой теме=)
Игорь Шунин
Игорь Шунин
5 588