Почему требует константу? С++

Требует что-бьі end бьіла константой, в 3х строках где long. Что я не так сделал понять не могу
codepad. org/73qvtffI - код в нормальном виде. (пробел после org)

#include "stdafx.h"
#include <iostream>
#include "math.h"
#include <conio.h>
#include <stdio.h>

using namespace std;
int main(){
cout << "This program solves an example of Newton's cooling law:\n";
cout << "T'(t) = -r[T(t) - E], where T is the temperature of the cooling\n";
cout << "object, t is time, r governs the rate of cooling and E is\n";
cout << "ambient temperature.\n";
long double E = 0;
cout << "\nPlease input a value for E:\n> ";
cin >> E;
long double r = 0;
cout << "\nPlease input a value for r:\n>> ";
cin >> r;
long double T0 = 0;
cout << "\nPlease input a value for T(0)\n> ";
cin >> T0;
long double dt = 0;
cout << "\nPlease input a value for the time interval, dt, in seconds : \n> ";
cin >> dt;
int end = 0;
cout << "\nPlease input the number of intervals to calculate : \n> ";
cin >> end;
long double TPrime[end + 2];
long double Temp[end + 2];
long double Time[end + 2];
Time[1] = 0;
TPrime[1] = -r*(T0 - E); // TPrime is the ~derivative of T.
Temp[1] = T0;
for (int i = 1; i<end + 2; i++) {
TPrime[i + 1] = -r*(Temp[i] - E);
Temp[i + 1] = Temp[i] + TPrime[i + 1] * dt;
Time[i + 1] = Time[i] + dt;
cout << Time[i] << "\t" << Temp[i] << endl;
}
return 0;
}