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Question

Постройте таблицу истинности для сложных суждений: 
а) (а ˄ b) → c; 
б) a→ (b˄c); 
в) a ˅ (b˄c).

Вадим Зобков · Accepted Answer

а) 
 
| a | b | c | (a ˄ b) | (a ˄ b) → c | 
|---|---|---|---------|-------------| 
| 0 | 0 | 0 |    0    |       1     | 
| 0 | 0 | 1 |    0    |       1     | 
| 0 | 1 | 0 |    0    |       1     | 
| 0 | 1 | 1 |    0    |       1     | 
| 1 | 0 | 0 |    0    |       1     | 
| 1 | 0 | 1 |    0    |       1     | 
| 1 | 1 | 0 |    1    |       0     | 
| 1 | 1 | 1 |    1    |       1     | 
 
б) 
 
| a | b | c | b ˄ c | a → (b ˄ c) | 
|---|---|---|-------|-------------| 
| 0 | 0 | 0 |   0   |         1       | 
| 0 | 0 | 1 |   0   |         1       | 
| 0 | 1 | 0 |   0   |         1       | 
| 0 | 1 | 1 |   1   |         1       | 
| 1 | 0 | 0 |   0   |         0       | 
| 1 | 0 | 1 |   0   |         0       | 
| 1 | 1 | 0 |   0   |         0       | 
| 1 | 1 | 1 |   1   |         1       | 
 
в) 
 
| a | b | c | b ˄ c | a ˅ (b ˄c) | 
|---|---|---|-------|-------------| 
| 0 | 0 | 0 |   0   |         0       | 
| 0 | 0 | 1 |   0   |         0       | 
| 0 | 1 | 0 |   0   |         0       | 
| 0 | 1 | 1 |   1   |         1       | 
| 1 | 0 | 0 |   0   |         1       | 
| 1 | 0 | 1 |   0   |         1       | 
| 1 | 1 | 0 |   0   |         1       | 
| 1 | 1 | 1 |   1   |         1       |

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