⇢ 
Андрей Добров
Артур
1) ∜(2∛3) = 24^(1/12)
2) log12log24∜(2∛3) = log(12, log(24, 24^(1/12))) = log(12, 1/12) = -1
3) ∛(∛3) = 3^(1/9)
4) log3log3∛(∛3) = log(3, log(3, 3^(1/9))) = -2
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1) ∜(2∛3) = 24^(1/12)
2) log12log24∜(2∛3) = log(12, log(24, 24^(1/12))) = log(12, 1/12) = -1
3) ∛(∛3) = 3^(1/9)
4) log3log3∛(∛3) = log(3, log(3, 3^(1/9))) = -2