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берется так
Int = 1/2 INT d(2x+1) / [ (2x+1) * ln^(2/3) (2x+1) ] = t=(2x+1)
= 1/2 INT dt/ [ t * ln^(2/3 t] = z= ln t dz = dt/t
= 1/2 Int dz / z^(2/3) =
= 1/2 Int z^(- 2/3) dz =
= 1/2 * z^(1 - 2/3)/ (1 - 2/3) + C=
= 3/2 * ln^(1/3) (2x+1) + C
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