Какое решение будет у логарифмов?

log3 (81) = log3 (3^4) = 4
log5 (1/625) = log5 [625^(-1)] = log5 [(5^4)^(-1)] = log5 [5^(-4)] = -4

log2 (0,125) = log2 (1/8) = log2 (8^(-1)] = log2 [(2^3)^(-1)] = log2 [2^(-3] = -3

lg (1000) = lg 10^3 = 3

log4 (8) = log(2^2) [2^3] = 1/2 * log2 [2^3] = 1/2 * 3 = 3/2

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log(a) [a^n] = n

log(a^n) [a^m] = 1/n * m