⇢ 
Иван
Тэране
Ответ
[2x \ (2x+y) - 4x^2 \ (2x+y)^2] : [2x \ (2x+y)(2x-y) - 1 \ (2x-y)] =
= [2x*(2x+y) - 4x^2]\(2x+y)^2 : [2x - (2x+y)] \ (2x+y)(2x-y) =
= (4x^2 + 2xy - 4xy^2)\(2x+y)^2 : (2x - 2x - y)\(2x+y)(2x-y) =
= 2xy\(2x+y)^2 * (2x+y)(2x-y)\(-y) =
= 2xy\(-y) * (2x+y)(2x-y)\(2x+y)^2 =
= (-2)x * (2x-y)\(2x+y) =
= -2x*(2x-y)\(2x+y)
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