здравствуйте) помогите пожалуйста решить задания по алгебре, очень нужно:)

Ответ
1) 12m^4 \ k^3 * k^6 \ 9m^2 =
= (12\9) * (m^4 \ m^2) * (k^6 \ k^3) =
= 4/3 * m^(4-2) * k^(6-3) =
= 4\3 * m^2 * k^3

2) 3x^2 \(16-y^2) : 15x^5 \(4+y) =
= 3x^2 \ (4+y)(4-y) * (4+y) \ 15x^5 =
= (3\15) * ( x^2 \ x^5) * [(4+y) \ (4+y)(4-y)] =
= 1/5 * x^(2-5) * 1\(4-y) =
= 1\5 * x^(-3) * 1\(4-y) =
= 1 \ {5*x^3 * (4-y)}

3) (x^2-1) \ (x^2-4) * (5x+10) \ (x+1) =
= (x+1)(x-1) \ (x+2)(x-2) * 5*(x+2) \ (x+1) =
= (x+1)(x-1) \ (x+1) * 5*(x+2) \ (x+2)(x-2) =
= (x-1) * 5\(x-2) =
= 5*(x-1) \ (x-2)

4) [2x\(x-2) - 1\(x+2)] : (6x^2+9x+6) \ (x^2-4) =
= [2x*(x+2) - 1*(x-2)] \(x-2)(x+2) : 3*(2x^2+3x+2) \ (x+2)(x-2) =
= (2x^2 + 4x - x + 2) \(x-2)(x+2) * (x+2)(x-2) \ 3*(2x^2+3x+2) =
= (2x^2+3x+2) \ 3(2x^2+3x+2) * (x+2)(x-2) \ (x-2)(x+2) =
= 1/3