Программирование на C++

 #include  

#include  

using namespace std; 

int main() { 

    ifstream inp("input.txt"); 

    if (!inp.is_open()) exit(0); 

    size_t n; 

    inp >> n; 

    auto x = new double[n]; 

    for (size_t i = 0; i < n; ++i) inp >> x[i]; 

    auto y = new double[n]; 

    for (size_t i = 0; i < n; ++i) inp >> y[i]; 

    auto sum = 0.0; 

    for (size_t i = 0; i < n; ++i) sum += x[i] * y[i]; 

    auto avg = sum / n; 

    cout  n; 

    auto x = new double[n]; 

    auto y = new double[n]; 

    for (size_t i = 0; i < n; ++i) { 

        inp >> x[i]; 

        inp >> y[i]; 

    } 

    auto sum = 0.0; 

    for (size_t i = 0; i < n; ++i) sum += x[i] * y[i]; 

    auto avg = sum / n; 

    cout  n1; 

    inp2 >> n2; 

    if (n1 != n2) puts("ERROR"); 

    else { 

        auto x = new double[n1]; 

        auto y = new double[n2]; 

        for (size_t i = 0; i < n1; ++i) { 

            inp1 >> x[i]; 

            inp2 >> y[i]; 

        } 

        auto sum = 0.0; 

        for (size_t i = 0; i < n1; ++i) sum += x[i] * y[i]; 

        auto avg = sum / n1; 

        cout

 #include  

 

using namespace std; 

 

 

int main(){ 

    freopen("input.txt", "r", stdin); 

    int n; 

    cin >> n; 

    double a[n], b[n], s = 0; 

    for(int i = 0; i < n; i++) cin >> a[i]; 

    for(int i = 0; i < n; i++){ cin >> b[i]; s += a[i] * b[i]; } 

    cout > n; 

    double a[n], b[n], s = 0; 

    for(int i = 0; i < n; i++){ cin >> a[i] >> b[i]; s += a[i] * b[i]; } 

    cout