Работа по алгебре на тему <<Показательная функиция>>.10 класс

a). 16^(2/7) *16^(12/7) =
16^(2/7 + 12/7) = 16^(14/7) =
16^2 = 256
б). (a^(2/3) -3a^(5/3))/a^(2/3) =
(a^(2/3))/(a^(2/3)) - 3*(a^(5/3))/(a^(2/3)) =
1 - 3*a^(5/3 - 2/3) =
1 - 3*a^(3/3) = 1 - 3*a^1 =
1 - 3*a = (при а = 3) =
1 - 3*3 = 1 - 9 = -8
в). 81^(1/4) -64^(2/3) +216^(1/3) =
(3^4)^(1/4) -(4^3)^(2/3) +(6^3)^(1/3) =
3^(4*1/4) -4^(3*2/3) +6^(3*1/3) =
3 -4^2 +6 = 3-16+6 = -7
г). ((4x)^2 *x^5)/(x^4 *2x^3) =
(16*x^2*x^5)/(2*x^4*x^3) =
8x^7/x^7 = 8
д). (a^-5 *b^-7)/((3a)^2 *b^-3) * 27/(a^-7 *b^-4) =
(a^-5 *b^-7 *27)/(9*a^2 *b^-3 *a^-7 *b^-4) =
(3*a^-5 *b^-7)/(a^-5 *b^-7) = 3
е). (17a^6*b^2 -(9a^3*b)^2) : (8a^6*b^3) =
(17a^6*b^2 -81a^6*b^2) : (8a^6*b^3) =
-64a^6*b^2/(8a^6*b^3) =
-8/b = (при b = 4) = -8/4 = -2
ж). (8(m^3)^4 +17(m^4)^3)/(5m^6)^2 =
(8m^12 +17m^12)/25m^12 =
(25m^12)/(25m^12) = 1
з). (47^(1/2) -15^0,5)^(1/5) * (V47 + V15)^(1/5) =
(47^0,5 -15^0,5)^(1/5) * (47^0,5 +15^0,5)^(1/5) =
((47^0,5 -15^0,5)(47^0,5 +15^0,5))^(1/5) =
((47^0,5)^2 -(15^0,5)^2)^(1/5) =
(47 -15)^(1/5) = 32^(1/5) =
(2^5)^(1/5) = 2
3.а). (x^3 -x+4)^(1/3) = x
x^3 -x +4 = x^3
x^3 -x -x^3 = -4
-x = -4
х = 4
4.а). 2^(x^2 -1) = (1/2)^(1-x)
2^(x^2 -1) = 2^(x-1)
x^2 -1 = х -1
x^2 -x = 0
x(x-1) = 0
x1 = 0; x2 = 1

я могу все решить. но высылать??? платно???