НК Наталья Каминская =[(3^2·2·2^3·3^2]^(1/4) = [3^(2+2)·2^(1+3)]^(1/4) = = (3^4·2^4)^(1/4) =[(3·2)^4]^(1/4) = (6^4)^(1/4) = 6^(4·1/4)=6^(4/4)=6^1=6