ГА
Ганишер Ахмадов
вычислить sin 13пи/6, cos 450 градусов, tg -11пи/6, ctg 5пи/4
sin 13пи/6= sin(12пи+π/6)=sin(12пи/6+π/6)=sin(2пи+π/6)= sin(π/6)=1/2=0.5
cos 450 °= cos (360 °+90°)= cos (90°)=0
tg (-11пи/6)= - tg(11пи/6)= - tg(12пи-π/6)=- tg(12пи/6-π/6)= - tg(2π-π/6)=- tg(-π/6)=
= tg(π/6)=1/√3
ctg 5пи/4= ctg (4пи+π/4)= ctg (4пи/4+π/4)= ctg (пи+π/4)= ctg (π/4)=1
Удачи!