ЛД
Любовь Дакиева
x^2 + 11x -x + 2 = 0,
x^2 + 10x + 2 = 0,
D = 10^2 - 4*1*2 = 92
x1,2 = [-10 +,-V92]/2 =
= [-10 +,-2V23]/2 =
=-5 +,-V23
V - кв.корень
ОТВЕТ:
x1 = [-10 + V92]/2 = -5+V23,
x2 = [-10 - V92]/2 = -5 - V23