посогите решить 1. y'*cosx=(y+1)*sinx 2.y''-4y'+20y=0

1. dy/dx*1/(y+1)=sinx/cosx, dy/(y+1)=tgxdx, int dy/(y+1)=int tgxdx, ln(y+1)=-ln(cosx)+lnC, y=C/cosx -1.
2. y=sin4x e^2x C1+cos4x e^2x C2.