Решите уравнение sin6x+ctg3x*cos6x=cos3x

Ответ. sin(6*x)+ctg(3*x)*cos(6*x)=cos(3*x); 2*sin(3*x)*cos(3*x)+ctg(3*x)*((cos(3*x))^2-(sin(3*x))^2)-cos(3*x)=0; cos(3*x)*(2*sin(3*x)+((cos(3*x))^2-(sin(3*x))^2)/(sin(3*x))-1)=0; 1).cos(3*x)=0;
2. 2*sin(3*x)+(1/(sin(3*x))-2*(sin(3*x))-1=0; 1/(sin(3*x))-1=0;

2). sin(3*x)=1;