Ми
Михаил
y = (x + 2y) / (2x - 3y)
2y= (2x +4y) / (2x - 3y)
2y= 1+ 7y / (2x - 3y)
2y - 1= 7y / (2x - 3y)
2x -3y = 7y/(2y - 1)
2x = 3y + 7y /(2y - 1)
2x = (6y^2 - 3y + 7y)/(2y - 1)
x = (3y^2+2y)/ (2y-1)
Ответ x = (3*y^2+2*y)/(2*y-1).
Асимптота x = (3*y^2+2*y)/(2*y-1) =~= 3/2*y+1