СС
Сергей Сыров
Ответ
5 * 6^(log5 x) = 72 + 3 * x^(log5 6)
x^(log5 6) = 6^(log5 x) [так как a^(logc b) = b^(logc a)] =>
=>
5 * 6^(log5 x) = 72 + 3 * 6^(log5 x)
5 * 6^(log5 x) - 3 * 6^(log5 x) = 72
2 * 6^(log5 x) = 72
6^(log5 x) = 36
6^(log5 x) = 6^2
log5 x = 2
x = 5^2
x = 25
Ответ.