Программа на C++ с переводом Char в Int и наоборот при переводе возвращает НИЧЕГО

Question

Программа на C++ с переводом Char в Int и наоборот при переводе возвращает НИЧЕГО

Доброго времени суток, господа, прошу откликнуться и помочь! Написал парочку функций для перевода Int в Char и наоборот и написал программу для теста:

 #include   

 

#define INT_MIN -2147483648  

 

#define INT_MAX 2147483647  

 

  

 

int Char2Int(char string[]) {  

 

    bool negative = false;  

 

    int outputValue = 0;  

 

    int stringLength = 0;  

 

    while (string[stringLength] != '\0') {  // count the number of characters in the string  

 

        stringLength++;  

 

    }  

 

    for (int i = 0; i < stringLength; i++) {  

 

        if (string[i] == '-') {  

 

            negative = true;  // remember that the input string is negative  

 

        } else if (string[i] >= '0' && string[i]  INT_MAX) {  

 

        return "";  // return an empty string if the input is out of range  

 

    }  

 

  

 

    // Handle the special case where the input integer is 0  

 

    if (inputNumber == 0) {  

 

        resultString[0] = '0';  

 

        resultString[1] = '\0';  

 

        return resultString;  

 

    }  

 

  

 

    // Convert the integer to a string  

 

    int absoluteInputNumber;  

 

    if (inputNumber < 0) {  

 

        absoluteInputNumber = inputNumber * -1;  // take the absolute value of inputNumber  

 

        resultString[0] = '-';  // add a minus sign to the beginning of the string  

 

    } else {  

 

        absoluteInputNumber = inputNumber;  

 

    }  

 

    int digit, reversedNumber = 0, resultIndex = 0;  

 

    while (absoluteInputNumber > 0) {  

 

        digit = absoluteInputNumber % 10;  

 

        reversedNumber = reversedNumber * 10 + digit;  

 

        absoluteInputNumber = absoluteInputNumber / 10;  

 

    }  

 

    while (reversedNumber > 0) {  

 

        resultString[resultIndex + 1] = (reversedNumber % 10) + '0';  // start at resultIndex + 1 to skip the minus sign  

 

        resultIndex++;  

 

        reversedNumber = reversedNumber / 10;  

 

    }  

 

    resultString[resultIndex + 1] = '\0';  // add a null terminator to the end of the string  

 

    return resultString;  // return a pointer to the character array  

 

}  

 

  

 

  

 

int main() {  

 

    int inputNumber = 12345;  

 

    printf("Integer: %d\n", inputNumber);  

 

    printf("String: %s\n", Int2Char(inputNumber));  

 

    int outputNumber = Char2Int(Int2Char(inputNumber));  // convert the string back to an integer  

 

    printf("Output: %d\n", outputNumber);  

 

    return 0;  

 

}

Ожидаю вывод:

Integer: 12345
String: 12345
Output: 12345

Получаю:

Integer: 12345
String:
Output: 0

Знатоки, в чем может быть проблема?

Дмитрий Дровняшин

122

21.12.2022

Похожие вопросы

Answer 1 · 2022-12-20 21:13:38

 #include  

 

#define INT_MIN -2147483648 

#define INT_MAX 2147483647 

 

int Char2Int(char string[]) { 

    bool negative = false; 

    int outputValue = 0; 

    int stringLength = 0; 

 

    // skip leading whitespace characters 

    while (string[stringLength] == ' ') { 

        stringLength++; 

    } 

 

    for (int i = stringLength; string[i] != '\0'; i++) { 

        if (string[i] == '-') { 

            negative = true; 

        } else if (string[i] >= '0' && string[i]  INT_MAX/10) { 

                return 0; 

            } 

            outputValue = outputValue * 10 + (string[i] - '0'); 

        } else { 

            return 0; 

        } 

    } 

 

    // check for negative overflow 

    if (negative && outputValue == INT_MIN) { 

        return 0; 

    } 

 

    if (negative) { 

        outputValue *= -1; 

    } 

 

    return outputValue; 

} 

 

char* Int2Char(int inputNumber) { 

    static char resultString[32]; 

 

    // check for out-of-range input 

    if (inputNumber < INT_MIN || inputNumber > INT_MAX) { 

        return ""; 

    } 

 

    // handle the special case of input integer 0 

    if (inputNumber == 0) { 

        resultString[0] = '0'; 

        resultString[1] = '\0'; 

        return resultString; 

    } 

 

    int absoluteInputNumber; 

    int resultIndex = 0; 

    if (inputNumber < 0) { 

        absoluteInputNumber = inputNumber * -1; 

        resultString[resultIndex++] = '-'; 

    } else { 

        absoluteInputNumber = inputNumber; 

    } 

 

    // convert the integer to a string 

    while (absoluteInputNumber > 0) { 

        resultString[resultIndex++] = (absoluteInputNumber % 10) + '0'; 

        absoluteInputNumber /= 10; 

    } 

 

    resultString[resultIndex] = '\0'; 

 

    // reverse the result string 

    for (int i = 0; i < resultIndex / 2; i++) { 

        char temp = resultString[i]; 

        resultString[i] = resultString[resultIndex - i - 1]; 

        resultString[resultIndex - i - 1] = temp; 

    } 

 

    return resultString; 

} 

 

 

int main() { 

    int inputNumber = 12345; 

    printf("Integer: %d\n", inputNumber); 

    printf("String: %s\n", Int2Char(inputNumber)); 

    int outputNumber = Char2Int(Int2Char(inputNumber)); 

    printf("Output: %d\n", outputNumber); 

    return 0; 

}

Борис

2 589

Лучший ответ

20.12.2022

Answer 2 · 2022-12-20 21:26:39

 char* Int2Char(int inputNumber)  

{ 

 

    static char resultString[17]{'0'};  // define the character array as a static local variable   

    char reverse[17]{}; //reverse buffer 

    // Convert the integer to a string   

    int it = 0, rev_it = 0; //forvard and revers iterator 

    if (inputNumber < 0) //add negative as needed 

    { 

        resultString[it++] = '-'; inputNumber = -inputNumber; 

    } 

 

    while (inputNumber)  

    { 

        reverse[rev_it++] = '0' + inputNumber % 10; 

        inputNumber /= 10; 

    } 

 

    while (rev_it) //copy from reverse to string 

    { 

        resultString[it++] = reverse[--rev_it]; 

    } 

    return resultString;  // return a pointer to the character array   

}