Помогите написать программу по этому условию

 #include  

int main() 

{ 

	size_t n, m; 

	double x; 

	std::cin >> n >> m; 

	auto res = std::make_shared(n, 0); 

	for (size_t i = 0; i < n; i++) 

	{ 

		for (size_t j = 0; j < m; j++) 

		{ 

			std::cin >> x; 

			res[i] += x > 0; 

		} 

	} 

	for (size_t i = 0; i < n; i++) std::cout

 #include 

#include 



using namespace std;



int main() {

  int n, m;

  cin >> n >> m;

  vector a(n, vector(m));

  for (auto &row: a) {

    for (auto &v: row) { cin >> v; }

  }



  vector b(a.size(), 0);

  for (int i = 0; i < a.size(); ++i) {

    for (auto v: a[i]) { b[i] += v > 0; }

  }



  for (auto v: b) { cout

 /* программа на языке Си */ 

 

#include  

#include  

#include  

 

int main() 

{ 

 int n,m,**a,*q,x,y; 

 

 do 

 { 

  printf("Kolichestvo strok = "); 

  scanf("%d", &n); 

  if(n < 1) printf("n > 0\n"); 

 }while(n < 1); 

 

 do 

 { 

  printf("Kolichestvo stobcov = "); 

  scanf("%d", &m); 

  if(m < 1) printf("m > 0\n"); 

  else if(n == m) printf("n != m\n"); 

 }while(m < 1 || m == n); 

 

 a = (int**) malloc(sizeof(int*) * n); 

 for(x = 0; x < n; x++) 

  a[x] = (int*) malloc(sizeof(int) * m); 

 

 q = (int*) malloc(sizeof(int) * n); 

 

 srand(time(NULL)); 

 for(x = 0; x < n; x++) 

 { 

  q[x] = 0; 

  for(y = 0; y < m; y++) 

  { 

   a[x][y] = rand() % 41 - 20; /* [-20;20] */ 

   printf("%d\t",a[x][y]); 

   if(a[x][y] > 0) q[x]++; 

  } 

  putchar('\n'); 

 } 

 putchar('\n'); 

 

 for(x = 0; x < n; x++) 

  printf("%d\n", q[x]); 

 putchar('\n'); 

 

 if(q == (int*) NULL) exit(1); 

 free(q); 

 q = (int*) NULL; 

 

 if(a == (int**) NULL) exit(1); 

 for(x = 0; x < n; x++) 

 { 

  if(a[x] == (int*) NULL) exit(1); 

 

  free(a[x]); 

 

  a[x] = (int*) NULL; 

 } 

 free(a); 

 a = (int**) NULL; 

 

 return 0; 

}