⇢ An
Anastasia
Ев
Евгений
№1
sin(-27π/4)=-sin(27π/4)=-sin(3π/4)=-sin(π/4)=√2/2
cos(31π/4)=cos(π/4)=√2/2
итого:...=8:((-√2/2)•(√2/2))=-16
№2
...=5•5^(log₅2)=125•2=250.
Похожие вопросы
№1
sin(-27π/4)=-sin(27π/4)=-sin(3π/4)=-sin(π/4)=√2/2
cos(31π/4)=cos(π/4)=√2/2
итого:...=8:((-√2/2)•(√2/2))=-16
№2
...=5•5^(log₅2)=125•2=250.