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Ответ
x^ {log2 (x)} = 16
ОДЗ: x > 0
log2 [x^ {log2 (x)} = log2 (16)
log2 (x) * log2 (x) = log2 (2^4)
[log2 (x)]^2 = 4 * log2 (2)
[log2 (x)]^2 = 4
log2 (x) = +- 2
x1 = 2^2 = 4
x2 = 2^(-2) = 1/4
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