Решите пожалуйста. 1)Sx(√x+1)^2*dx 2)S2/3x+5*dx 3)S(2x+1)√2x+√1*dx

∫x(√x+1) dx = ∫x+2x^(3/2)+x dx = x/3 + 4/5x^(5/2) + x/2 + C

∫2/(3x+5) dx = 2∫1/(3x+5) dx = 2/3∫1/u du //(u = 3x+5; du = 3dx)// = 2/3ln(u) + C = 2/3ln(3x+5) + C

∫(2x+1)√(2x+1) dx = ∫(2x+1)^(3/2) dx = 1/5(2x+1)^(5/2) + C