2sin^2x-3sin2x-4cos2x=4 2sin^2x-3sin2x-4cos2x=4

Ответ. 2*(sin(x))^2-3*sin(2*x)-4*cos(2*x)=4; 2*(sin(x))^2-6*sin(x)*cos(x)-4*(cos(x))^2+(sin(x))^2=4;3*(sin(x))^2-6*sin(x)*cos(x)-4*(cos(x))^2=4*(cos(x))^2+4*(sin(x))^2; -(sin(x))^2-6*sin(x)*cos(x)-8*(cos(x))^2=0;
tg(x)^2+6*tg(x)+8=0; (tg(x)+2)*(tg(x)+4)=0; tg(x1)=-2; tg(x2)=-4;