помогите с алгеброй. во вложении №4

13\(x-2) + 2\(x-13) = 2
13*(x-13) + 2*(x-2) = 2*(x-2)(x-13)
13x - 169 + 2x - 4 = 2x^2 - 4x - 26x + 52
2x^2 - 45x + 225 = 0
x1,2 = [45 +- V{45^2 - 4*2*225)] \2*2 = [45 +- 15] \4
x1 = 15
x2 = 7,5