Помогите решить, запуталась. х^2(х-2)(6х+1)+х (5х+3)=1

Question

Лина Лукьянова · Accepted Answer

Раскрываем скобки 
x^2 * (6x^2 - 11x - 2) + 5x^2 + 3x - 1 = 0 
6x^4 - 11x^3 - 2x^2 + 5x^2 + 3x - 1 = 0 
6x^4 - 11x^3 + 3x^2 + 3x - 1 = 0 
6x^4 - 6x^3 - 5x^3 + 5x^2 - 2x^2 + 2x + x - 1 = 0 
6x^3 * (x-1) - 5x^2 * (x-1) - 2x * (x-1) + (x-1) = 0 
x1 = 1 
6x^3 - 5x^2 - 2x + 1 = 0 
6x^3 - 6x^2 + x^2 - x - x + 1 = 0 
6x^2 * (x-1) + x * (x-1) - (x-1) = 0 
x2 = 1 
6x^2 + x - 1 = 0 
х3 = 1/3 
х4 = -1/2

Азер Заманов · Answer

Ответ. х^2(х-2)(6х+1)+х (5х+3)-1=(2*x+1)*(3*x-1)*(x-1)^2=0; x1=-0,5; x2=1/3; x3=1;