Дм Дмитрий ОДЗ: x>0 log(2, x) + log(4, x) + log(16, x) = 14 log(2, x) + 1/2*log(2, x) + 1/4*log(2, x) = 14 7/4*log(2, x) = 14 --> log(2, x) = 8 --> x = 2^8 = 256 Ответ: 256