Помогите сделать Логарифмы))

Ответ. 1 log(45,3)- log(5,3) + 16^( log(2,4) =2+Log(5,3)-Log(5,3)+4=6;
2. log(50, 5) - log(2,5) + 3^(log(5,3))=2+Log(2,5)-Log(2,5)+5=7;
3. Log(25,5) (3^2/5) =2*3^0,4;

Ответ
log3 45 - log3 5 + 16^(log4 2) =
= log3 (45/5) + (4^2)^(log4 2) =
= log3 9 + 4^(2log4 2) =
= log3 3^2 + 4^(log4 2^2) =
= 2 + 2^2 = 6

log5 50 - log5 2 + 3^(log3 5) =
= log5 (50\2) + 5 =
= log5 5^2 + 5 =
= 25 + 5 = 30

log5 25V3 степени 5 ???
(cтепень чего: 3 или (25V3)^5)

log2 4^3 = log2 (2^2)^3 = log2 2^6 = 6

5^(х+3) + 5^х =
= 5^x * 5^3 + 5^x =
= 5^x * (5^3+1) = 126 * 5^x

3^(х+3) - 3^x =
= 3^x * 3^3 - 3^x =
= 3^x * (3^3 - 1) = 26 * 3^x

log3 (2х+1) = log3 (х-2)
ОДЗ: 2x+1>0 и (x-2)>0 или
x> -1\2 и x>2 => x>2
(2x+1) = (x-2)
x = -3 <2 (не удовлетвиряет ОДЗ =>
решений нет.

log(???) (2х-1)-log(???) (3х+1) = 5

5^(2х+3) > 5^(х+1)
2x+3 > x+1
x > -2

(3/5)^(2х+1) < (3/5)^(х-1)
2x+1 > x-1
x > -2

log(1/2) (3х+5) - дальше что?