Помогите упростить выражение с корнями

Ответ
32^(1/4) * 4^(1/4 * 1/3) + 64^(1/4) * (1/2)^(1/3 * 1/4) - 3 * 2^(1/3) * 2^(1/4 * 1/3) =
= (2^4)^(1/4) * (2^2)^(1/12) + (2^6)^(1/4) * [2*(-1)]^(1/12)] - 3 * 2^(1/3 + 1/12) =
= 2^(4/4) * 2^(2/12) + 2^(6/4) * 2^(-1/12) - 3 * 2^(5/12) =
= 2^(1+1/6) + 2^(3/2 - 1/12) - 3 * 2^(5/12) =
= 2^(7/6) + 2^(17/12) - 3 * 2^(5/12) =
= 2^(14/12) + 2^(17/12) - 3 * 2^(5/12) =
= 2^(5/12) * [2^(9/12) + 2^(12/12) - 3 * 1] =
= 2^(5/12) * [2^(3/4) + 2 - 3] =
= 2^(5/12) * [2^(3/4) -1]