Дмитрий Нет, не так. 2* sin(x) + cos(4x) = 0 2*sin(x) - 1 + 2cos(2x) = 0 -cos(2x) +2cos(2x) = 0 cos(2x) = 0 cos(2x) = 1/2 x = -π/4 + π*k /2 x = π/6 + π*k x = -π/6 + π*k k - целое