Ad Adenios ∫e^(2x)/(e^(2x)+7) dx = 1/2∫e^u/(e^u+7) du //(u = 2x; du = 2dx)// = 1/2∫1/t dt //(t = e^u+7; dt = e^u du)// = 1/2ln(t) + C = 1/2ln(e^(2x)+7) + C