Решите интегралы плз 1)(x^(1/4))/(4+x^(1/2)) 2)(2x-6)/((x+1)*((x^2)+3))) 3)1/(5+3*cosx) 4)x/(sqr((x^2)-4))

Ответ. INT((x^(1/4))/(4+x^(1/2))*dx=|x^0,5=y^2; x=y^4; dx=4*y^3*dy|=INT(y*4*y^3*dy)/(1+y^2)=INT(4/(y^2+1)+4*y^2-4)*dx=(4/3)*y^3-4*y+4*arctg(y)+C; INT((x^(1/4))/(4+x^(1/2))*dx=(4/3)*x^(3/4)-4*x^0,25+4*arctg(x^0,25)+C;