Помогите решить плиз: 3log1/2 1/8= . 16log4 3 -0,25log2 3 = . log3(-log1/3 27)= . logx1/4=-2.

3log1/2 1/8=3log1/2 (1/2)³=3*3*log1/2 (1/2)=9*1=9 .
16log4 3 -0,25log2 3 =16log₂² 3 -0,25log₂ 3= 16*½*log₂ 3 -0,25log₂ 3=8* log₂ 3 -0,25log₂ 3= log₂ 3⁸ -log₂ 3^(0.25)= log₂ (3⁸/3^(0.25))= log₂ (3^(8-0.25)= log₂ (3^(7.75)=7.75 log₂ 3 .
log3(-log1/3 27)= log3(-log1/3 (1/3)⁻³)= log3(-1*(-3)log1/3 (1/3))= log3(-1*(-3)*1)= log3(3) =1 .
logx1/4=-2.
х⁻²=1/4
х⁻²=2⁻²
х=2
удачи!