Показательные уравнения алгебра 10 класс. Помогите пожалуйста.

2) (1/3)^(4-3x) = 27
3^(3x-4) = 3^(3)
(3x-4) = 3
x = 7/3

3) (2 * 4^(1/3))^x = 8
(2 * 2^(2/3))^x = 2^3
(2^(5/3))^x = 2^(3)
2^((5/3) * x) = 2^(3)
5x/3 = 3
5x = 9
x= 9/5

4) 17^(x) * 17^(x+5) = 17
17^(x+x+5) = 17^(1)
(2x+5) = 1
x = - 2

5) (2/5)x = (4/9)^(x/2)
(2/5)^x = ((2/3)^x
x = 0

6) 4^(x-3) + 4^(x) = 65
4^(x)/4^(3) + 4^(x) = 65
4^(x) * (1/64 + 1) = 65
4^(x) = 65*64/65
4^(x) = 64
4^(x) = 4^(3)
x = 3

7) 9^(x) - 10*3^(x) + 9 = 0
(3^x)^2 - 10*3^x + 9 = 0 -----> 3^x = t
t^2 - 10*t + 9 = 0 -----> t1 = 1; t2 = 9
3^x = t1 = 1 ------> 3^x = 3^0 -------> x1 = 0
3^x = t2 = 9 ------> 3^x = 3^2 -------> x2 = 2

8) аналогично

9) 3^{V(x+1)^2} = 3^1
{V(x+1)^2} = 1
(x+2)^2 = 1
(x+2)^2 - 1 = 0
((x+2) + 1)((x+2) - 1) = 0
(x+3)(x+1) = 0
x1 = -3; x2 = -1

10) (1/4 * 4^x)^x = 2^(2x+6)
[2^((-2) + x)]^x = 2^(2x+6)
2^{x*(x-2)} = 2^(2x+6)
x*(x-2) = 2x+6)
x^2 - 4x - 6 = 0
x1 = 2 - V10
x2 = 2+V10

11) аналогично номеру 7