ВН
Виталий Назаров
Ответ. 3*(sin(x))^2-cos(x)+1=0; 3*(cos(x))^2+cos(x)-4=(3*cos(x)+4)*(cos(x)-1)=0; cos(x1)=1;
3sin^2(x) - cos(x) + 1 = 3sin^2(x) - 1 + 2sin^2(x/2) + 1 = 12sin^2(x/2)cos^2(x/2) + 2sin^2(x/2) = 0
sin^2(x/2)(6cos^2(x/2) + 1) = 0
6cos^2(x/2) + 1 != 0
sin^2(x/2) = 0;
x = 2pk, k E Z