Найти корни уравнения Алгебра

x^2 - 11 = (x - 11)^2
x^2 -11= x^2 -22x+121
22x= 121+11
x= 132|22= 6

х²–11=х²–22х+121
22х=121+11
22х=132
х=6

1.
(2x - 3)^2 = (2x + 5)^2
4x^2 - 12x + 9 = 4x^2 + 20x + 25
4x^2 - 4x^2 - 12x - 20x + 9 - 25 = 0
-32x = 16 |:(-16)
2x = 1
x = 1/2 = 0.5

x^2 - 11 = (x - 11)^2
x^2 - 11 = x^2 - 22x + 121
x^2 - x^2 + 22x - 11 - 121 = 0
22x = 132 |:22
x = 6

(2x + 5)/(5x + 2) = -1
2x + 5 = -5x - 2
2x + 5x = -2 - 5
7x = -7
x = -7/7 = -1

x^3 + 7x^2 = 4x + 28
x^2(x + 7) = 4(x + 7)
x^2 = 4
x = ±√4 = ±2

2.
(6с - 5)(6с + 5) - (6с - 5)^2 = 36с^2 - 25 - 36с^2 + 60c - 25 = 60c - 50 = 10(6c - 5) при с=11
10(6*11 - 5) = 10(66-5) = 10*61 = 610

(2а^2)^3 : (2а^7) = (2а^6)/(2a^7) = 1/a при а = 125
1/125 = 0,008
(вроде там в степени должна стоять 7,насколько я смог различить)

√170^2 - 26^2 = √(170 - 26)(170 + 26) = √144*196 = 12*13 = 156

3.
√7 - 6x = 7 |↑2
7 - 6x = 49
6x = -42
x = -42/6 = -7

√1/(3 - 2x) = 0.5 |↑2
1/(3 - 2x) = 0.25
0.25(3 - 2x) = 1
0.75 - 0.5x = 1
0.5x = -0.25
x = -0.25/0.5 = -1/2 = -0.5

А