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Сначала разберёмся с определителями:

 ㅤ   | 1   3  –1|                                                                                                                            | 8   3  –1|                                                                                                                            | 1   8  –1|                                                                                                                             | 1   3   8|

D = | 2  –1   4| = 1 × (–1) × 1 + 3 × 4 × (–2) + (–1) × 2 × 2 – ((–2) × (–1) × (–1) + 2 × 4 × 1 + 1 × 2 × 3) = –1 – 24 – 4 – 12 = –41, D₁ = |–1  –1   4| = 8 × (–1) × 1 + 3 × 4 × 4 + (–1) × (–1) × 2 – (4 × (–1) × (–1) + 2 × 4 × 8 + 1 × (–1) × 3) = –8 + 48 + 2 – 65 = –23, D₂ = | 2  –1   4| = 1 × (–1) × 1 + 8 × 4 × (–2) + (–1) × 2 × 4 – ((–2) × (–1) × (–1) + 4 × 4 × 1 + 1 × 2 × 8) = –1 – 64 – 8 – 30 = –103, D₃ = | 2  –1  –1| = 1 × (–1) × 4 + 3 × (–1) × (–2) + 8 × 2 × 2 – ((–2) × (–1) × 8 + 2 × (–1) × 1 + 4 × 2 × 3) = –4 + 6 + 32 – 38 = –4.

    |–2   2   1|                                                                                                                            | 4   2   1|                                                                                                                            |–2   4   1|                                                                                                                             |–2   2   4| 

D ≠ 0; x = D₁/D = 23/41, y = D₂/D = 103/41, z = D₃/D = 4/41.

Ответ: (23/41; 103/41; 4/41).