Помогите найти значение выражения.

a
b = a * q
c = a * q^2

__log(2) b = log(2) (a * q) = log(2) a + log(2) q
__log(a^2) c = 2 * log(a) (a * q^2) = 2 * (log(a) a + 2*log(a) q) =
= 2 + 4*log(a) q)
__log(c) Va) = 1\2 * 1\log(a) c = 1\2 * 1\(log(a) (a * q^2) =
= 1 \ 2*(log(a) a + 2*log(a) q) = 1\2*(1 + 2*log(a) q) = 1\2 + log(a) q
__log(a) 4 = 2 * 1\log(2) a = 2\log(2) a
__2*log(c) 2 = 2 * 1\log(2) c = 2 \ log(2) (a * q^2) = 2 \ (log(2) a + 2*log(2) q)
=>
Подставляй в выражение

(log(a^2) c - log(c) Va) =
= 1\2 * (log(a) c - log(c) a) = 1\2 * (log(a) c - 1\log(a) c) =
= 1\2 * ((log(a) c)^2 - 1)\log(a) c =
= 1\2 * ((log(a1) (a1 * q^2) - 1) \ log(a) (a1 * q^2) =

(log(a) 4 - 2*log(c) 2) = 2 * [1\log(2) a - 1\log(2) c] = 2 * (log(2) c - log(2) a)\log(2) a * log(2) c

q=a^x
a
b = a•q=a^(1+x)
c = a•q^2=a^(1+2x)

log[a^(1+x)]2•(1+2x-1/(1+2x)) - числ.
4•(log[a]2-log[a]2/(1+2x)) - знам.
=
4х (1+х) (1+2х) - числ.
(1+х) (1+2х) •4•2х - знам.

После сокращения получаем 0,5.

Вот как я решил.